Define working directory in VS project

This commit is contained in:
aurhat
2017-11-19 13:34:34 +01:00
parent 830f8c0cf7
commit 7cc454c11a
+10
View File
@@ -106,18 +106,28 @@
</PropertyGroup>
<PropertyGroup Condition="'$(Configuration)|$(Platform)'=='Release|Win32'">
<TargetName>ac_client</TargetName>
<LocalDebuggerWorkingDirectory>..\..</LocalDebuggerWorkingDirectory>
<DebuggerFlavor>WindowsLocalDebugger</DebuggerFlavor>
</PropertyGroup>
<PropertyGroup Condition="'$(Configuration)|$(Platform)'=='Profile|Win32'">
<TargetName>ac_client</TargetName>
<LocalDebuggerWorkingDirectory>..\..</LocalDebuggerWorkingDirectory>
<DebuggerFlavor>WindowsLocalDebugger</DebuggerFlavor>
</PropertyGroup>
<PropertyGroup Condition="'$(Configuration)|$(Platform)'=='Debug|Win32'">
<TargetName>ac_client</TargetName>
<LocalDebuggerWorkingDirectory>..\..</LocalDebuggerWorkingDirectory>
<DebuggerFlavor>WindowsLocalDebugger</DebuggerFlavor>
</PropertyGroup>
<PropertyGroup Condition="'$(Configuration)|$(Platform)'=='Standalone|Win32'">
<TargetName>ac_server</TargetName>
<LocalDebuggerWorkingDirectory>..\..</LocalDebuggerWorkingDirectory>
<DebuggerFlavor>WindowsLocalDebugger</DebuggerFlavor>
</PropertyGroup>
<PropertyGroup Condition="'$(Configuration)|$(Platform)'=='Standalone Debug|Win32'">
<TargetName>ac_server</TargetName>
<LocalDebuggerWorkingDirectory>..\..</LocalDebuggerWorkingDirectory>
<DebuggerFlavor>WindowsLocalDebugger</DebuggerFlavor>
</PropertyGroup>
<ItemDefinitionGroup Condition="'$(Configuration)|$(Platform)'=='Release|Win32'">
<Midl>